0.6a^2-8a-10=0

Solution for 0.6a^2-8a-10=0 equation:

0.6a^2-8a-10=0

a = 0.6; b = -8; c = -10;
Δ = b2-4ac
Δ = -82-4·0.6·(-10)
Δ = 88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88}=\sqrt{4*22}=\sqrt{4}*\sqrt{22}=2\sqrt{22}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{22}}{2*0.6}=\frac{8-2\sqrt{22}}{1.2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{22}}{2*0.6}=\frac{8+2\sqrt{22}}{1.2}
$